Search a number
-
+
172448620753 is a prime number
BaseRepresentation
bin1010000010011010111…
…1010010000011010001
3121111010020111121022211
42200212233102003101
510311133321331003
6211115524232121
715313303043113
oct2404657220321
9544106447284
10172448620753
1167153829192
122950883b641
13133533373c6
1484bcd513b3
1547447c796d
hex2826bd20d1

172448620753 has 2 divisors, whose sum is σ = 172448620754. Its totient is φ = 172448620752.

The previous prime is 172448620739. The next prime is 172448620793. The reversal of 172448620753 is 357026844271.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116822454849 + 55626165904 = 341793^2 + 235852^2 .

It is an emirp because it is prime and its reverse (357026844271) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 172448620753 - 225 = 172415066321 is a prime.

It is a super-3 number, since 3×1724486207533 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 172448620697 and 172448620706.

It is not a weakly prime, because it can be changed into another prime (172448620793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86224310376 + 86224310377.

It is an arithmetic number, because the mean of its divisors is an integer number (86224310377).

Almost surely, 2172448620753 is an apocalyptic number.

It is an amenable number.

172448620753 is a deficient number, since it is larger than the sum of its proper divisors (1).

172448620753 is an equidigital number, since it uses as much as digits as its factorization.

172448620753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2257920, while the sum is 49.

The spelling of 172448620753 in words is "one hundred seventy-two billion, four hundred forty-eight million, six hundred twenty thousand, seven hundred fifty-three".