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1729136423881 = 7475212313161
BaseRepresentation
bin11001001010011000100…
…011111111001111001001
320010022012111020111212101
4121022120203333033021
5211312232411031011
63402204310313401
7235632420044536
oct31123043771711
96108174214771
101729136423881
11607360484049
1223b150358861
13c7097c18089
145d9951dbd8d
152eea37132c1
hex192988ff3c9

1729136423881 has 4 divisors (see below), whose sum is σ = 1729139484564. Its totient is φ = 1729133363200.

The previous prime is 1729136423863. The next prime is 1729136423897. The reversal of 1729136423881 is 1883246319271.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 983994561225 + 745141862656 = 991965^2 + 863216^2 .

It is a cyclic number.

It is not a de Polignac number, because 1729136423881 - 223 = 1729128035273 is a prime.

It is a super-2 number, since 2×17291364238812 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1729136423821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 409060 + ... + 1904101.

It is an arithmetic number, because the mean of its divisors is an integer number (432284871141).

Almost surely, 21729136423881 is an apocalyptic number.

It is an amenable number.

1729136423881 is a deficient number, since it is larger than the sum of its proper divisors (3060683).

1729136423881 is an equidigital number, since it uses as much as digits as its factorization.

1729136423881 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3060682.

The product of its digits is 3483648, while the sum is 55.

The spelling of 1729136423881 in words is "one trillion, seven hundred twenty-nine billion, one hundred thirty-six million, four hundred twenty-three thousand, eight hundred eighty-one".

Divisors: 1 747521 2313161 1729136423881