Base | Representation |
---|---|
bin | 10000001000111110… |
… | …100010011111100001 |
3 | 1122201210100122210011 |
4 | 100020332202133201 |
5 | 240443100343441 |
6 | 11543404204521 |
7 | 1152315442012 |
oct | 201076423741 |
9 | 48653318704 |
10 | 17330481121 |
11 | 7393671a78 |
12 | 3437b39741 |
13 | 1832604175 |
14 | ba5949009 |
15 | 6b6707581 |
hex | 408fa27e1 |
17330481121 has 4 divisors (see below), whose sum is σ = 17333060292. Its totient is φ = 17327901952.
The previous prime is 17330481109. The next prime is 17330481137. The reversal of 17330481121 is 12118403371.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3298894096 + 14031587025 = 57436^2 + 118455^2 .
It is a cyclic number.
It is not a de Polignac number, because 17330481121 - 25 = 17330481089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (17330481151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1279480 + ... + 1292953.
It is an arithmetic number, because the mean of its divisors is an integer number (4333265073).
Almost surely, 217330481121 is an apocalyptic number.
It is an amenable number.
17330481121 is a deficient number, since it is larger than the sum of its proper divisors (2579171).
17330481121 is an equidigital number, since it uses as much as digits as its factorization.
17330481121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2579170.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 17330481121 its reverse (12118403371), we get a palindrome (29448884492).
The spelling of 17330481121 in words is "seventeen billion, three hundred thirty million, four hundred eighty-one thousand, one hundred twenty-one".
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