1743640113713 has 4 divisors (see below), whose sum is σ = 1743649762368. Its totient is φ = 1743630465060.

The previous prime is 1743640113707. The next prime is 1743640113739. The reversal of 1743640113713 is 3173110463471.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1743640113713 - 2³² = 1739345146417 is a prime.

It is a super-2 number, since 2×1743640113713² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1743640113793) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4547981 + ... + 4916442.

It is an arithmetic number, because the mean of its divisors is an integer number (435912440592).

Almost surely, 2^{1743640113713} is an apocalyptic number.

It is an amenable number.

1743640113713 is a deficient number, since it is larger than the sum of its proper divisors (9648655).

1743640113713 is an equidigital number, since it uses as much as digits as its factorization.

1743640113713 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9648654.

The product of its (nonzero) digits is 127008, while the sum is 41.

The spelling of 1743640113713 in words is "one trillion, seven hundred forty-three billion, six hundred forty million, one hundred thirteen thousand, seven hundred thirteen".