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1748322380113 is a prime number
BaseRepresentation
bin11001011100010000001…
…000100110100101010001
320012010201121000001222221
4121130100020212211101
5212121031012130423
63415100200101041
7240212026014151
oct31342010464521
96163647001887
101748322380113
1161450644aa21
12242a05764781
13c8b34a637ba
1460895340761
1530727c80e5d
hex19710226951

1748322380113 has 2 divisors, whose sum is σ = 1748322380114. Its totient is φ = 1748322380112.

The previous prime is 1748322380071. The next prime is 1748322380191. The reversal of 1748322380113 is 3110832238471.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1528467361344 + 219855018769 = 1236312^2 + 468887^2 .

It is a cyclic number.

It is not a de Polignac number, because 1748322380113 - 213 = 1748322371921 is a prime.

It is a super-2 number, since 2×17483223801132 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1748322380113.

It is not a weakly prime, because it can be changed into another prime (1748322320113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 874161190056 + 874161190057.

It is an arithmetic number, because the mean of its divisors is an integer number (874161190057).

Almost surely, 21748322380113 is an apocalyptic number.

It is an amenable number.

1748322380113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1748322380113 is an equidigital number, since it uses as much as digits as its factorization.

1748322380113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 193536, while the sum is 43.

The spelling of 1748322380113 in words is "one trillion, seven hundred forty-eight billion, three hundred twenty-two million, three hundred eighty thousand, one hundred thirteen".