Base | Representation |
---|---|
bin | 11001111010001000000… |
… | …111000110111000101010 |
3 | 20022012112010202021112111 |
4 | 121322020013012320222 |
5 | 213132224401301010 |
6 | 3441523211232534 |
7 | 242425654342126 |
oct | 31721007067052 |
9 | 6265463667474 |
10 | 1780400025130 |
11 | 627077443451 |
12 | 24907844874a |
13 | cbb776ba43c |
14 | 62259696586 |
15 | 314a3ea858a |
hex | 19e881c6e2a |
1780400025130 has 16 divisors (see below), whose sum is σ = 3204745293024. Its totient is φ = 712154399440.
The previous prime is 1780400025113. The next prime is 1780400025133. The reversal of 1780400025130 is 315200040871.
It is a junction number, because it is equal to n+sod(n) for n = 1780400025092 and 1780400025101.
It is not an unprimeable number, because it can be changed into a prime (1780400025133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 780549 + ... + 2042071.
It is an arithmetic number, because the mean of its divisors is an integer number (200296580814).
Almost surely, 21780400025130 is an apocalyptic number.
1780400025130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1780400025130 is a deficient number, since it is larger than the sum of its proper divisors (1424345267894).
1780400025130 is a wasteful number, since it uses less digits than its factorization.
1780400025130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1402661.
The product of its (nonzero) digits is 6720, while the sum is 31.
The spelling of 1780400025130 in words is "one trillion, seven hundred eighty billion, four hundred million, twenty-five thousand, one hundred thirty".
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