Base | Representation |
---|---|
bin | 1000001110110010011110… |
… | …01010000110011010011001 |
3 | 2101002101002102211112012001 |
4 | 10013121033022012122121 |
5 | 4333023423434424423 |
6 | 102255101115521001 |
7 | 3545463544311346 |
oct | 407311712063231 |
9 | 71071072745161 |
10 | 18100320233113 |
11 | 5849336996218 |
12 | 2043b68759161 |
13 | a13b119c2461 |
14 | 4680bb18b7cd |
15 | 215c6e29bcad |
hex | 10764f286699 |
18100320233113 has 4 divisors (see below), whose sum is σ = 18100395877648. Its totient is φ = 18100244588580.
The previous prime is 18100320233057. The next prime is 18100320233131. The reversal of 18100320233113 is 31133202300181.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-18100320233113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (18100320233173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37462203 + ... + 37942288.
It is an arithmetic number, because the mean of its divisors is an integer number (4525098969412).
Almost surely, 218100320233113 is an apocalyptic number.
It is an amenable number.
18100320233113 is a deficient number, since it is larger than the sum of its proper divisors (75644535).
18100320233113 is an equidigital number, since it uses as much as digits as its factorization.
18100320233113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75644534.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 18100320233113 its reverse (31133202300181), we get a palindrome (49233522533294).
The spelling of 18100320233113 in words is "eighteen trillion, one hundred billion, three hundred twenty million, two hundred thirty-three thousand, one hundred thirteen".
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