Base | Representation |
---|---|
bin | 10000110111111000… |
… | …100101010011111001 |
3 | 1201202122011202200220 |
4 | 100313320211103321 |
5 | 244101031331303 |
6 | 12153435450253 |
7 | 1210652526612 |
oct | 206770452371 |
9 | 51678152626 |
10 | 18117448953 |
11 | 775791160a |
12 | 36175b6989 |
13 | 19296732c6 |
14 | c3c280c09 |
15 | 710858053 |
hex | 437e254f9 |
18117448953 has 4 divisors (see below), whose sum is σ = 24156598608. Its totient is φ = 12078299300.
The previous prime is 18117448949. The next prime is 18117448967. The reversal of 18117448953 is 35984471181.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 18117448953 - 22 = 18117448949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 18117448896 and 18117448905.
It is not an unprimeable number, because it can be changed into a prime (18117448253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3019574823 + ... + 3019574828.
It is an arithmetic number, because the mean of its divisors is an integer number (6039149652).
Almost surely, 218117448953 is an apocalyptic number.
It is an amenable number.
18117448953 is a deficient number, since it is larger than the sum of its proper divisors (6039149655).
18117448953 is an equidigital number, since it uses as much as digits as its factorization.
18117448953 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6039149654.
The product of its digits is 967680, while the sum is 51.
The spelling of 18117448953 in words is "eighteen billion, one hundred seventeen million, four hundred forty-eight thousand, nine hundred fifty-three".
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