Base | Representation |
---|---|
bin | 10000111000110010… |
… | …101100100110000001 |
3 | 1201210200211202001221 |
4 | 100320302230212001 |
5 | 244113431330022 |
6 | 12155142155041 |
7 | 1211226156262 |
oct | 207062544601 |
9 | 51720752057 |
10 | 18132683137 |
11 | 7765477248 |
12 | 3620722a81 |
13 | 192c87840a |
14 | c402c8969 |
15 | 711d66cc7 |
hex | 438cac981 |
18132683137 has 4 divisors (see below), whose sum is σ = 18184939056. Its totient is φ = 18080427220.
The previous prime is 18132683131. The next prime is 18132683183. The reversal of 18132683137 is 73138623181.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 18132683137 - 211 = 18132681089 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 18132683093 and 18132683102.
It is not an unprimeable number, because it can be changed into a prime (18132683131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26127439 + ... + 26128132.
It is an arithmetic number, because the mean of its divisors is an integer number (4546234764).
Almost surely, 218132683137 is an apocalyptic number.
It is an amenable number.
18132683137 is a deficient number, since it is larger than the sum of its proper divisors (52255919).
18132683137 is an equidigital number, since it uses as much as digits as its factorization.
18132683137 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52255918.
The product of its digits is 145152, while the sum is 43.
The spelling of 18132683137 in words is "eighteen billion, one hundred thirty-two million, six hundred eighty-three thousand, one hundred thirty-seven".
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