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18132947892113 = 28164530063673
BaseRepresentation
bin1000001111101111001111…
…11010101111011110010001
32101012111022022112100001212
410013313213322233132101
54334042234130021423
6102322054455505505
73551030231656535
oct407674772573621
971174268470055
1018132947892113
11586115a3a635a
12204a353688295
13a16c11592a62
144698d4597bc5
15216a2d91b578
hex107de7eaf791

18132947892113 has 4 divisors (see below), whose sum is σ = 18197477956068. Its totient is φ = 18068417828160.

The previous prime is 18132947892097. The next prime is 18132947892161. The reversal of 18132947892113 is 31129874923181.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15916014502144 + 2216933389969 = 3989488^2 + 1488937^2 .

It is a cyclic number.

It is not a de Polignac number, because 18132947892113 - 24 = 18132947892097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (18132947892413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32265031556 + ... + 32265032117.

It is an arithmetic number, because the mean of its divisors is an integer number (4549369489017).

Almost surely, 218132947892113 is an apocalyptic number.

It is an amenable number.

18132947892113 is a deficient number, since it is larger than the sum of its proper divisors (64530063955).

18132947892113 is an equidigital number, since it uses as much as digits as its factorization.

18132947892113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64530063954.

The product of its digits is 5225472, while the sum is 59.

The spelling of 18132947892113 in words is "eighteen trillion, one hundred thirty-two billion, nine hundred forty-seven million, eight hundred ninety-two thousand, one hundred thirteen".

Divisors: 1 281 64530063673 18132947892113