Base | Representation |
---|---|
bin | 1000001111111100111011… |
… | …10001111010110110001011 |
3 | 2101020012021021112021122011 |
4 | 10013332131301322312023 |
5 | 4334202310231000021 |
6 | 102325311440240351 |
7 | 3551410252602661 |
oct | 407763561726613 |
9 | 71205237467564 |
10 | 18140294000011 |
11 | 586428a056a07 |
12 | 204b8639100b7 |
13 | a178124bb471 |
14 | 469dd008ac31 |
15 | 216d0d800de1 |
hex | 107f9dc7ad8b |
18140294000011 has 2 divisors, whose sum is σ = 18140294000012. Its totient is φ = 18140294000010.
The previous prime is 18140293999981. The next prime is 18140294000051. The reversal of 18140294000011 is 11000049204181.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 18140294000011 - 213 = 18140293991819 is a prime.
It is not a weakly prime, because it can be changed into another prime (18140294000051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9070147000005 + 9070147000006.
It is an arithmetic number, because the mean of its divisors is an integer number (9070147000006).
Almost surely, 218140294000011 is an apocalyptic number.
18140294000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
18140294000011 is an equidigital number, since it uses as much as digits as its factorization.
18140294000011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 31.
The spelling of 18140294000011 in words is "eighteen trillion, one hundred forty billion, two hundred ninety-four million, eleven", and thus it is an aban number.
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