Base | Representation |
---|---|
bin | 1010101000111111011… |
… | …1100101110010000001 |
3 | 122110211210212002101211 |
4 | 2222033313211302001 |
5 | 10443334344402433 |
6 | 215551144330121 |
7 | 16131004155316 |
oct | 2521767456201 |
9 | 573753762354 |
10 | 182802340993 |
11 | 70587179478 |
12 | 2b518173941 |
13 | 143133b119c |
14 | 8bc206cd0d |
15 | 4b4d7568cd |
hex | 2a8fde5c81 |
182802340993 has 2 divisors, whose sum is σ = 182802340994. Its totient is φ = 182802340992.
The previous prime is 182802340937. The next prime is 182802340999. The reversal of 182802340993 is 399043208281.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 168503682064 + 14298658929 = 410492^2 + 119577^2 .
It is a cyclic number.
It is not a de Polignac number, because 182802340993 - 221 = 182800243841 is a prime.
It is not a weakly prime, because it can be changed into another prime (182802340999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 91401170496 + 91401170497.
It is an arithmetic number, because the mean of its divisors is an integer number (91401170497).
Almost surely, 2182802340993 is an apocalyptic number.
It is an amenable number.
182802340993 is a deficient number, since it is larger than the sum of its proper divisors (1).
182802340993 is an equidigital number, since it uses as much as digits as its factorization.
182802340993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 49.
The spelling of 182802340993 in words is "one hundred eighty-two billion, eight hundred two million, three hundred forty thousand, nine hundred ninety-three".
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