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1863550006113 = 3621183335371
BaseRepresentation
bin11011000111100100001…
…111000111001101100001
320121011011000002222002210
4123013210033013031201
5221013022300143423
63544034132032333
7251431335456555
oct33074417071541
96534130088083
101863550006113
116593664398a4
122612031626a9
131069692c9b13
14662a6919865
153371dc94b93
hex1b1e43c7361

1863550006113 has 4 divisors (see below), whose sum is σ = 2484733341488. Its totient is φ = 1242366670740.

The previous prime is 1863550006103. The next prime is 1863550006121. The reversal of 1863550006113 is 3116000553681.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1863550006113 - 218 = 1863549743969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1863550006103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310591667683 + ... + 310591667688.

It is an arithmetic number, because the mean of its divisors is an integer number (621183335372).

Almost surely, 21863550006113 is an apocalyptic number.

It is an amenable number.

1863550006113 is a deficient number, since it is larger than the sum of its proper divisors (621183335375).

1863550006113 is an equidigital number, since it uses as much as digits as its factorization.

1863550006113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 621183335374.

The product of its (nonzero) digits is 64800, while the sum is 39.

Adding to 1863550006113 its reverse (3116000553681), we get a palindrome (4979550559794).

The spelling of 1863550006113 in words is "one trillion, eight hundred sixty-three billion, five hundred fifty million, six thousand, one hundred thirteen".

Divisors: 1 3 621183335371 1863550006113