Base | Representation |
---|---|
bin | 10001100001101100… |
… | …100111101110101011 |
3 | 1210120112012000201220 |
4 | 101201230213232223 |
5 | 302020123044303 |
6 | 12351215313123 |
7 | 1234231326345 |
oct | 214154475653 |
9 | 53515160656 |
10 | 18818956203 |
11 | 7a878a0373 |
12 | 379251b7a3 |
13 | 1a0babc758 |
14 | ca74cc295 |
15 | 752227053 |
hex | 461b27bab |
18818956203 has 4 divisors (see below), whose sum is σ = 25091941608. Its totient is φ = 12545970800.
The previous prime is 18818956153. The next prime is 18818956207. The reversal of 18818956203 is 30265981881.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30265981881 = 3 ⋅10088660627.
It is a cyclic number.
It is not a de Polignac number, because 18818956203 - 210 = 18818955179 is a prime.
It is a super-2 number, since 2×188189562032 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (18818956207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3136492698 + ... + 3136492703.
It is an arithmetic number, because the mean of its divisors is an integer number (6272985402).
Almost surely, 218818956203 is an apocalyptic number.
18818956203 is a deficient number, since it is larger than the sum of its proper divisors (6272985405).
18818956203 is an equidigital number, since it uses as much as digits as its factorization.
18818956203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6272985404.
The product of its (nonzero) digits is 829440, while the sum is 51.
The spelling of 18818956203 in words is "eighteen billion, eight hundred eighteen million, nine hundred fifty-six thousand, two hundred three".
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