Base | Representation |
---|---|
bin | 1000100111000101101001… |
… | …00110011010011010011011 |
3 | 2111001012011211121100211201 |
4 | 10103202310212122122123 |
5 | 4440213340411344212 |
6 | 104134422024335031 |
7 | 3663012020516602 |
oct | 423426446323233 |
9 | 74035154540751 |
10 | 18935245809307 |
11 | 6040435689273 |
12 | 215993b614477 |
13 | a74780635539 |
14 | 496683ba8a39 |
15 | 22c83881cb57 |
hex | 1138b499a69b |
18935245809307 has 2 divisors, whose sum is σ = 18935245809308. Its totient is φ = 18935245809306.
The previous prime is 18935245809257. The next prime is 18935245809331. The reversal of 18935245809307 is 70390854253981.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 18935245809307 - 215 = 18935245776539 is a prime.
It is not a weakly prime, because it can be changed into another prime (18935245809397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9467622904653 + 9467622904654.
It is an arithmetic number, because the mean of its divisors is an integer number (9467622904654).
Almost surely, 218935245809307 is an apocalyptic number.
18935245809307 is a deficient number, since it is larger than the sum of its proper divisors (1).
18935245809307 is an equidigital number, since it uses as much as digits as its factorization.
18935245809307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 65318400, while the sum is 64.
The spelling of 18935245809307 in words is "eighteen trillion, nine hundred thirty-five billion, two hundred forty-five million, eight hundred nine thousand, three hundred seven".
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