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191340601 is a prime number
BaseRepresentation
bin10110110011110…
…10000000111001
3111100001002221221
423121322000321
5342440344401
630553032041
74512240214
oct1331720071
9440032857
10191340601
1199009031
12540b5621
13308449ba
141b5aa77b
1511be87a1
hexb67a039

191340601 has 2 divisors, whose sum is σ = 191340602. Its totient is φ = 191340600.

The previous prime is 191340557. The next prime is 191340623. The reversal of 191340601 is 106043191.

191340601 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 190440000 + 900601 = 13800^2 + 949^2 .

It is an emirp because it is prime and its reverse (106043191) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 191340601 - 213 = 191332409 is a prime.

It is a super-2 number, since 2×1913406012 = 73222451182082402, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (191340631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 95670300 + 95670301.

It is an arithmetic number, because the mean of its divisors is an integer number (95670301).

Almost surely, 2191340601 is an apocalyptic number.

It is an amenable number.

191340601 is a deficient number, since it is larger than the sum of its proper divisors (1).

191340601 is an equidigital number, since it uses as much as digits as its factorization.

191340601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 191340601 is about 13832.5919841511. The cubic root of 191340601 is about 576.2386415103.

Adding to 191340601 its reverse (106043191), we get a palindrome (297383792).

The spelling of 191340601 in words is "one hundred ninety-one million, three hundred forty thousand, six hundred one".