Base | Representation |
---|---|
bin | 1000110010011001111000… |
… | …10101011011100000000011 |
3 | 2112102100210200010122202211 |
4 | 10121030330111123200003 |
5 | 10013101143422142311 |
6 | 105033204422522551 |
7 | 4033055320552462 |
oct | 431147425334003 |
9 | 75370720118684 |
10 | 19324070115331 |
11 | 6180323891343 |
12 | 2201173b96457 |
13 | aa23378222b7 |
14 | 4ab40ba049d9 |
15 | 2379e401e821 |
hex | 11933c55b803 |
19324070115331 has 4 divisors (see below), whose sum is σ = 19324121516200. Its totient is φ = 19324018714464.
The previous prime is 19324070115319. The next prime is 19324070115421. The reversal of 19324070115331 is 13351107042391.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19324070115331 is a prime.
It is a super-2 number, since 2×193240701153312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (19324070115631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25132326 + ... + 25889803.
It is an arithmetic number, because the mean of its divisors is an integer number (4831030379050).
Almost surely, 219324070115331 is an apocalyptic number.
19324070115331 is a deficient number, since it is larger than the sum of its proper divisors (51400869).
19324070115331 is an equidigital number, since it uses as much as digits as its factorization.
19324070115331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51400868.
The product of its (nonzero) digits is 68040, while the sum is 40.
The spelling of 19324070115331 in words is "nineteen trillion, three hundred twenty-four billion, seventy million, one hundred fifteen thousand, three hundred thirty-one".
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