Base | Representation |
---|---|
bin | 1011010000011001110… |
… | …0100100010011100001 |
3 | 200111011002202012201112 |
4 | 2310012130210103201 |
5 | 11132021202232403 |
6 | 224501024313105 |
7 | 16654115106311 |
oct | 2640634442341 |
9 | 614132665645 |
10 | 193381680353 |
11 | 75015a0a744 |
12 | 3158b172795 |
13 | 1530b1121c4 |
14 | 950711b441 |
15 | 506c4009d8 |
hex | 2d067244e1 |
193381680353 has 2 divisors, whose sum is σ = 193381680354. Its totient is φ = 193381680352.
The previous prime is 193381680343. The next prime is 193381680431. The reversal of 193381680353 is 353086183391.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 157844906209 + 35536774144 = 397297^2 + 188512^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-193381680353 is a prime.
It is a super-2 number, since 2×1933816803532 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (193381680343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 96690840176 + 96690840177.
It is an arithmetic number, because the mean of its divisors is an integer number (96690840177).
Almost surely, 2193381680353 is an apocalyptic number.
It is an amenable number.
193381680353 is a deficient number, since it is larger than the sum of its proper divisors (1).
193381680353 is an equidigital number, since it uses as much as digits as its factorization.
193381680353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 50.
The spelling of 193381680353 in words is "one hundred ninety-three billion, three hundred eighty-one million, six hundred eighty thousand, three hundred fifty-three".
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