Base | Representation |
---|---|
bin | 1011010011000111000… |
… | …1001011000111100011 |
3 | 200120000202101121021021 |
4 | 2310301301023013203 |
5 | 11140013234034444 |
6 | 225101110510311 |
7 | 20011122022312 |
oct | 2646161130743 |
9 | 616022347237 |
10 | 194108502499 |
11 | 753592099aa |
12 | 31752665397 |
13 | 153c5882c92 |
14 | 9575878279 |
15 | 50b1120584 |
hex | 2d31c4b1e3 |
194108502499 has 2 divisors, whose sum is σ = 194108502500. Its totient is φ = 194108502498.
The previous prime is 194108502407. The next prime is 194108502517. The reversal of 194108502499 is 994205801491.
194108502499 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 194108502499 - 211 = 194108500451 is a prime.
It is a super-2 number, since 2×1941085024992 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (194108500499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97054251249 + 97054251250.
It is an arithmetic number, because the mean of its divisors is an integer number (97054251250).
Almost surely, 2194108502499 is an apocalyptic number.
194108502499 is a deficient number, since it is larger than the sum of its proper divisors (1).
194108502499 is an equidigital number, since it uses as much as digits as its factorization.
194108502499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 52.
The spelling of 194108502499 in words is "one hundred ninety-four billion, one hundred eight million, five hundred two thousand, four hundred ninety-nine".
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