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195054902017 is a prime number
BaseRepresentation
bin1011010110101000101…
…1011001101100000001
3200122110201012200100021
42311222023121230001
511143433023331032
6225335035253441
720043433211503
oct2655213315401
9618421180307
10195054902017
11757a4452968
12319775aa281
1315516973cb1
149625431d73
155119265097
hex2d6a2d9b01

195054902017 has 2 divisors, whose sum is σ = 195054902018. Its totient is φ = 195054902016.

The previous prime is 195054901997. The next prime is 195054902071. The reversal of 195054902017 is 710209450591.

Together with next prime (195054902071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 191865024576 + 3189877441 = 438024^2 + 56479^2 .

It is a cyclic number.

It is not a de Polignac number, because 195054902017 - 219 = 195054377729 is a prime.

It is a super-2 number, since 2×1950549020172 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (195054902087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97527451008 + 97527451009.

It is an arithmetic number, because the mean of its divisors is an integer number (97527451009).

Almost surely, 2195054902017 is an apocalyptic number.

It is an amenable number.

195054902017 is a deficient number, since it is larger than the sum of its proper divisors (1).

195054902017 is an equidigital number, since it uses as much as digits as its factorization.

195054902017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 113400, while the sum is 43.

The spelling of 195054902017 in words is "one hundred ninety-five billion, fifty-four million, nine hundred two thousand, seventeen".