Base | Representation |
---|---|
bin | 1011010110111011010… |
… | …1110110110111111001 |
3 | 200122200011102121022212 |
4 | 2311232311312313321 |
5 | 11144113040443343 |
6 | 225350512224505 |
7 | 20045403220115 |
oct | 2655665666771 |
9 | 618604377285 |
10 | 195133140473 |
11 | 75834630647 |
12 | 3199983b135 |
13 | 15529c3863b |
14 | 963199a745 |
15 | 512106bc18 |
hex | 2d6ed76df9 |
195133140473 has 8 divisors (see below), whose sum is σ = 200866763328. Its totient is φ = 189453865104.
The previous prime is 195133140443. The next prime is 195133140479. The reversal of 195133140473 is 374041331591.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 195133140473 - 232 = 190838173177 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 195133140473.
It is not an unprimeable number, because it can be changed into a prime (195133140479) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13579586 + ... + 13593947.
It is an arithmetic number, because the mean of its divisors is an integer number (25108345416).
Almost surely, 2195133140473 is an apocalyptic number.
It is an amenable number.
195133140473 is a deficient number, since it is larger than the sum of its proper divisors (5733622855).
195133140473 is a wasteful number, since it uses less digits than its factorization.
195133140473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27173743.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 195133140473 in words is "one hundred ninety-five billion, one hundred thirty-three million, one hundred forty thousand, four hundred seventy-three".
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