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19538114521 is a prime number
BaseRepresentation
bin10010001100100011…
…111111011111011001
31212102122102001111011
4102030203333133121
5310003224131041
612550425333521
71261113143002
oct221443773731
955378361434
1019538114521
118316835692
1239533372a1
131ac4aa9113
14d34c121a9
15795430e81
hex48c8ff7d9

19538114521 has 2 divisors, whose sum is σ = 19538114522. Its totient is φ = 19538114520.

The previous prime is 19538114509. The next prime is 19538114549. The reversal of 19538114521 is 12541183591.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15186865225 + 4351249296 = 123235^2 + 65964^2 .

It is a cyclic number.

It is not a de Polignac number, because 19538114521 - 217 = 19537983449 is a prime.

It is a super-2 number, since 2×195381145212 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (19538114821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9769057260 + 9769057261.

It is an arithmetic number, because the mean of its divisors is an integer number (9769057261).

Almost surely, 219538114521 is an apocalyptic number.

It is an amenable number.

19538114521 is a deficient number, since it is larger than the sum of its proper divisors (1).

19538114521 is an equidigital number, since it uses as much as digits as its factorization.

19538114521 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43200, while the sum is 40.

It can be divided in two parts, 195381 and 14521, that added together give a palindrome (209902).

The spelling of 19538114521 in words is "nineteen billion, five hundred thirty-eight million, one hundred fourteen thousand, five hundred twenty-one".