Base | Representation |
---|---|
bin | 101100011011001101101101… |
… | …010100010101011100110001 |
3 | 221121210112202020020121210211 |
4 | 230123031231110111130301 |
5 | 201102133310433401432 |
6 | 1531314131450024121 |
7 | 56104020254644132 |
oct | 5433155524253461 |
9 | 847715666217724 |
10 | 195384191309617 |
11 | 57289a74380112 |
12 | 19ab6922418041 |
13 | 850385b5b35ab |
14 | 3636906a6bc89 |
15 | 178c5d045ed47 |
hex | b1b36d515731 |
195384191309617 has 2 divisors, whose sum is σ = 195384191309618. Its totient is φ = 195384191309616.
The previous prime is 195384191309519. The next prime is 195384191309653. The reversal of 195384191309617 is 716903191483591.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 153973949573376 + 41410241736241 = 12408624^2 + 6435079^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-195384191309617 is a prime.
It is not a weakly prime, because it can be changed into another prime (195384191306617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97692095654808 + 97692095654809.
It is an arithmetic number, because the mean of its divisors is an integer number (97692095654809).
Almost surely, 2195384191309617 is an apocalyptic number.
It is an amenable number.
195384191309617 is a deficient number, since it is larger than the sum of its proper divisors (1).
195384191309617 is an equidigital number, since it uses as much as digits as its factorization.
195384191309617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 44089920, while the sum is 67.
The spelling of 195384191309617 in words is "one hundred ninety-five trillion, three hundred eighty-four billion, one hundred ninety-one million, three hundred nine thousand, six hundred seventeen".
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