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1958042211793 is a prime number
BaseRepresentation
bin11100011111100100011…
…010010001010111010001
320221012001022212100221021
4130133210122101113101
5224040032301234133
64055302343555441
7261315053121643
oct34374432212721
96835038770837
101958042211793
11695445867568
1227759445bb81
131128479c6c65
146aaac294893
1535dee6c052d
hex1c7e46915d1

1958042211793 has 2 divisors, whose sum is σ = 1958042211794. Its totient is φ = 1958042211792.

The previous prime is 1958042211767. The next prime is 1958042211889. The reversal of 1958042211793 is 3971122408591.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1002385420864 + 955656790929 = 1001192^2 + 977577^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1958042211793 is a prime.

It is a super-3 number, since 3×19580422117933 (a number of 38 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1958042211793.

It is not a weakly prime, because it can be changed into another prime (1958042212793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 979021105896 + 979021105897.

It is an arithmetic number, because the mean of its divisors is an integer number (979021105897).

Almost surely, 21958042211793 is an apocalyptic number.

It is an amenable number.

1958042211793 is a deficient number, since it is larger than the sum of its proper divisors (1).

1958042211793 is an equidigital number, since it uses as much as digits as its factorization.

1958042211793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1088640, while the sum is 52.

The spelling of 1958042211793 in words is "one trillion, nine hundred fifty-eight billion, forty-two million, two hundred eleven thousand, seven hundred ninety-three".