Base | Representation |
---|---|
bin | 1011011010001010000… |
… | …0101010100001010001 |
3 | 200201220120120122011021 |
4 | 2312202200222201101 |
5 | 11202402000000311 |
6 | 230012520115441 |
7 | 20106030340444 |
oct | 2664240524121 |
9 | 621816518137 |
10 | 196000000081 |
11 | 76139988046 |
12 | 31ba0005b81 |
13 | 156376ca812 |
14 | 96b4b6b65b |
15 | 51721ee171 |
hex | 2da282a851 |
196000000081 has 2 divisors, whose sum is σ = 196000000082. Its totient is φ = 196000000080.
The previous prime is 195999999997. The next prime is 196000000111. The reversal of 196000000081 is 180000000691.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 154743890625 + 41256109456 = 393375^2 + 203116^2 .
It is a cyclic number.
It is not a de Polignac number, because 196000000081 - 215 = 195999967313 is a prime.
It is a super-2 number, since 2×1960000000812 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 195999999992 and 196000000055.
It is not a weakly prime, because it can be changed into another prime (196000000681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98000000040 + 98000000041.
It is an arithmetic number, because the mean of its divisors is an integer number (98000000041).
Almost surely, 2196000000081 is an apocalyptic number.
It is an amenable number.
196000000081 is a deficient number, since it is larger than the sum of its proper divisors (1).
196000000081 is an equidigital number, since it uses as much as digits as its factorization.
196000000081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 196000000081 in words is "one hundred ninety-six billion, eighty-one", and thus it is an aban number.
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