Base | Representation |
---|---|
bin | 1000111010111011100110… |
… | …01011010010011111100011 |
3 | 2120110101000210200020202201 |
4 | 10131131303023102133203 |
5 | 10032401203240330003 |
6 | 105415540351154031 |
7 | 4063166510404315 |
oct | 435356313223743 |
9 | 76411023606681 |
10 | 19617047980003 |
11 | 62835a8195411 |
12 | 2249ab9815917 |
13 | ac3b58897936 |
14 | 4bb6822a77b5 |
15 | 24043ee90b1d |
hex | 11d7732d27e3 |
19617047980003 has 2 divisors, whose sum is σ = 19617047980004. Its totient is φ = 19617047980002.
The previous prime is 19617047979989. The next prime is 19617047980007. The reversal of 19617047980003 is 30008974071691.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 19617047980003 - 29 = 19617047979491 is a prime.
It is not a weakly prime, because it can be changed into another prime (19617047980007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9808523990001 + 9808523990002.
It is an arithmetic number, because the mean of its divisors is an integer number (9808523990002).
Almost surely, 219617047980003 is an apocalyptic number.
19617047980003 is a deficient number, since it is larger than the sum of its proper divisors (1).
19617047980003 is an equidigital number, since it uses as much as digits as its factorization.
19617047980003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2286144, while the sum is 55.
The spelling of 19617047980003 in words is "nineteen trillion, six hundred seventeen billion, forty-seven million, nine hundred eighty thousand, three".
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