Base | Representation |
---|---|
bin | 10010010100111001… |
… | …101011011001011001 |
3 | 1212210101122211202122 |
4 | 102110321223121121 |
5 | 310300033021423 |
6 | 13012344111025 |
7 | 1264432246166 |
oct | 222471533131 |
9 | 55711584678 |
10 | 19678017113 |
11 | 8388800567 |
12 | 3992165475 |
13 | 1b17a81011 |
14 | d4962d06d |
15 | 7a28688c8 |
hex | 494e6b659 |
19678017113 has 2 divisors, whose sum is σ = 19678017114. Its totient is φ = 19678017112.
The previous prime is 19678017041. The next prime is 19678017119. The reversal of 19678017113 is 31171087691.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15260155024 + 4417862089 = 123532^2 + 66467^2 .
It is an emirp because it is prime and its reverse (31171087691) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19678017113 - 210 = 19678016089 is a prime.
It is not a weakly prime, because it can be changed into another prime (19678017119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9839008556 + 9839008557.
It is an arithmetic number, because the mean of its divisors is an integer number (9839008557).
Almost surely, 219678017113 is an apocalyptic number.
It is an amenable number.
19678017113 is a deficient number, since it is larger than the sum of its proper divisors (1).
19678017113 is an equidigital number, since it uses as much as digits as its factorization.
19678017113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63504, while the sum is 44.
The spelling of 19678017113 in words is "nineteen billion, six hundred seventy-eight million, seventeen thousand, one hundred thirteen".
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