Base | Representation |
---|---|
bin | 10010010111000101… |
… | …101011010001010001 |
3 | 1212212221201101012120 |
4 | 102113011223101101 |
5 | 310333431414003 |
6 | 13020134444453 |
7 | 1265356220214 |
oct | 222705532121 |
9 | 55787641176 |
10 | 19714716753 |
11 | 83a7497546 |
12 | 39a2503729 |
13 | 1b22560594 |
14 | d5046377b |
15 | 7a5bb7853 |
hex | 49716b451 |
19714716753 has 4 divisors (see below), whose sum is σ = 26286289008. Its totient is φ = 13143144500.
The previous prime is 19714716743. The next prime is 19714716761. The reversal of 19714716753 is 35761741791.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 19714716753 - 210 = 19714715729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 19714716696 and 19714716705.
It is not an unprimeable number, because it can be changed into a prime (19714716733) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3285786123 + ... + 3285786128.
It is an arithmetic number, because the mean of its divisors is an integer number (6571572252).
Almost surely, 219714716753 is an apocalyptic number.
It is an amenable number.
19714716753 is a deficient number, since it is larger than the sum of its proper divisors (6571572255).
19714716753 is an equidigital number, since it uses as much as digits as its factorization.
19714716753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6571572254.
The product of its digits is 1111320, while the sum is 51.
The spelling of 19714716753 in words is "nineteen billion, seven hundred fourteen million, seven hundred sixteen thousand, seven hundred fifty-three".
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