Base | Representation |
---|---|
bin | 11100110010011000011… |
… | …110100011011101011001 |
3 | 21000010012011101221111112 |
4 | 130302120132203131121 |
5 | 224402420213240203 |
6 | 4112443051110105 |
7 | 262631464633124 |
oct | 34623036433531 |
9 | 7003164357445 |
10 | 1978243102553 |
11 | 6a2a71727803 |
12 | 27b491742335 |
13 | 114716bab463 |
14 | 6ba671113bb |
15 | 366d2dbe6d8 |
hex | 1cc987a3759 |
1978243102553 has 2 divisors, whose sum is σ = 1978243102554. Its totient is φ = 1978243102552.
The previous prime is 1978243102543. The next prime is 1978243102609. The reversal of 1978243102553 is 3552013428791.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1674777633424 + 303465469129 = 1294132^2 + 550877^2 .
It is a cyclic number.
It is not a de Polignac number, because 1978243102553 - 210 = 1978243101529 is a prime.
It is not a weakly prime, because it can be changed into another prime (1978243102543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 989121551276 + 989121551277.
It is an arithmetic number, because the mean of its divisors is an integer number (989121551277).
Almost surely, 21978243102553 is an apocalyptic number.
It is an amenable number.
1978243102553 is a deficient number, since it is larger than the sum of its proper divisors (1).
1978243102553 is an equidigital number, since it uses as much as digits as its factorization.
1978243102553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 50.
The spelling of 1978243102553 in words is "one trillion, nine hundred seventy-eight billion, two hundred forty-three million, one hundred two thousand, five hundred fifty-three".
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