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1981225483 is a prime number
BaseRepresentation
bin111011000010111…
…0001101000001011
312010002000200102121
41312011301220023
513024143203413
6524332312111
7100045065406
oct16605615013
95102020377
101981225483
11927394036
12473612637
13257602993
1414b1acd3d
15b8e04b8d
hex76171a0b

1981225483 has 2 divisors, whose sum is σ = 1981225484. Its totient is φ = 1981225482.

The previous prime is 1981225471. The next prime is 1981225501. The reversal of 1981225483 is 3845221891.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1981225483 - 217 = 1981094411 is a prime.

It is a super-3 number, since 3×19812254833 (a number of 29 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1981225423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990612741 + 990612742.

It is an arithmetic number, because the mean of its divisors is an integer number (990612742).

Almost surely, 21981225483 is an apocalyptic number.

1981225483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1981225483 is an equidigital number, since it uses as much as digits as its factorization.

1981225483 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 138240, while the sum is 43.

The square root of 1981225483 is about 44510.9591336785. The cubic root of 1981225483 is about 1255.9662475125.

The spelling of 1981225483 in words is "one billion, nine hundred eighty-one million, two hundred twenty-five thousand, four hundred eighty-three".