198125441 has 2 divisors, whose sum is σ = 198125442. Its totient is φ = 198125440.

The previous prime is 198125437. The next prime is 198125453. The reversal of 198125441 is 144521891.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 188265841 + 9859600 = 13721^2 + 3140^2 .

It is an emirp because it is prime and its reverse (144521891) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 198125441 - 2² = 198125437 is a prime.

It is a super-3 number, since 3×198125441³ (a number of 26 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (198125401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99062720 + 99062721.

It is an arithmetic number, because the mean of its divisors is an integer number (99062721).

Almost surely, 2^198125441 is an apocalyptic number.

It is an amenable number.

198125441 is a deficient number, since it is larger than the sum of its proper divisors (1).

198125441 is an equidigital number, since it uses as much as digits as its factorization.

198125441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11520, while the sum is 35.

The square root of 198125441 is about 14075.7039255591. The cubic root of 198125441 is about 582.9707281901.

The spelling of 198125441 in words is "one hundred ninety-eight million, one hundred twenty-five thousand, four hundred forty-one".