198134081 has 2 divisors, whose sum is σ = 198134082. Its totient is φ = 198134080.

The previous prime is 198134063. The next prime is 198134143. The reversal of 198134081 is 180431891.

198134081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 194463025 + 3671056 = 13945^2 + 1916^2 .

It is an emirp because it is prime and its reverse (180431891) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 198134081 - 2¹⁰ = 198133057 is a prime.

It is a super-3 number, since 3×198134081³ (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (198134011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99067040 + 99067041.

It is an arithmetic number, because the mean of its divisors is an integer number (99067041).

Almost surely, 2^198134081 is an apocalyptic number.

It is an amenable number.

198134081 is a deficient number, since it is larger than the sum of its proper divisors (1).

198134081 is an equidigital number, since it uses as much as digits as its factorization.

198134081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 35.

The square root of 198134081 is about 14076.0108340396. The cubic root of 198134081 is about 582.9792022724.

The spelling of 198134081 in words is "one hundred ninety-eight million, one hundred thirty-four thousand, eighty-one".