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19813764365947 is a prime number
BaseRepresentation
bin1001000000101010000000…
…11000101111111001111011
32121011011210022021001120201
410200111000120233321323
510044112042134202242
6110050152342103031
74113332360163436
oct440250030577173
977134708231521
1019813764365947
116349a74493792
12228005971aa77
13b09578820bc6
144c6dc423681d
15245604eec4b7
hex12054062fe7b

19813764365947 has 2 divisors, whose sum is σ = 19813764365948. Its totient is φ = 19813764365946.

The previous prime is 19813764365917. The next prime is 19813764366043. The reversal of 19813764365947 is 74956346731891.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 19813764365947 - 27 = 19813764365819 is a prime.

It is a super-3 number, since 3×198137643659473 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 19813764365947.

It is not a weakly prime, because it can be changed into another prime (19813764365917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9906882182973 + 9906882182974.

It is an arithmetic number, because the mean of its divisors is an integer number (9906882182974).

Almost surely, 219813764365947 is an apocalyptic number.

19813764365947 is a deficient number, since it is larger than the sum of its proper divisors (1).

19813764365947 is an equidigital number, since it uses as much as digits as its factorization.

19813764365947 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 823011840, while the sum is 73.

The spelling of 19813764365947 in words is "nineteen trillion, eight hundred thirteen billion, seven hundred sixty-four million, three hundred sixty-five thousand, nine hundred forty-seven".