19814151813353 has 2 divisors, whose sum is σ = 19814151813354. Its totient is φ = 19814151813352.

The previous prime is 19814151813347. The next prime is 19814151813403. The reversal of 19814151813353 is 35331815141891.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17966433574489 + 1847718238864 = 4238683^2 + 1359308^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-19814151813353 is a prime.

It is a super-3 number, since 3×19814151813353³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 19814151813295 and 19814151813304.

It is not a weakly prime, because it can be changed into another prime (19814151113353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9907075906676 + 9907075906677.

It is an arithmetic number, because the mean of its divisors is an integer number (9907075906677).

Almost surely, 2^{19814151813353} is an apocalyptic number.

It is an amenable number.

19814151813353 is a deficient number, since it is larger than the sum of its proper divisors (1).

19814151813353 is an equidigital number, since it uses as much as digits as its factorization.

19814151813353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1555200, while the sum is 53.

The spelling of 19814151813353 in words is "nineteen trillion, eight hundred fourteen billion, one hundred fifty-one million, eight hundred thirteen thousand, three hundred fifty-three".