Base | Representation |
---|---|
bin | 10010011101000001… |
… | …110111011001000011 |
3 | 1220010220020212000112 |
4 | 102131001313121003 |
5 | 311034440143443 |
6 | 13034054541535 |
7 | 1301006313665 |
oct | 223501673103 |
9 | 56126225015 |
10 | 19814381123 |
11 | 8448779899 |
12 | 3a0b9678ab |
13 | 1b3a0b7394 |
14 | d5d7a8535 |
15 | 7ae802b18 |
hex | 49d077643 |
19814381123 has 16 divisors (see below), whose sum is σ = 20508635136. Its totient is φ = 19131850080.
The previous prime is 19814381107. The next prime is 19814381137. The reversal of 19814381123 is 32118341891.
It is a cyclic number.
It is not a de Polignac number, because 19814381123 - 24 = 19814381107 is a prime.
It is a super-3 number, since 3×198143811233 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (19814381143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1539053 + ... + 1551873.
It is an arithmetic number, because the mean of its divisors is an integer number (1281789696).
Almost surely, 219814381123 is an apocalyptic number.
19814381123 is a deficient number, since it is larger than the sum of its proper divisors (694254013).
19814381123 is a wasteful number, since it uses less digits than its factorization.
19814381123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13274.
The product of its digits is 41472, while the sum is 41.
The spelling of 19814381123 in words is "nineteen billion, eight hundred fourteen million, three hundred eighty-one thousand, one hundred twenty-three".
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