1981447283 has 2 divisors, whose sum is σ = 1981447284. Its totient is φ = 1981447282.

The previous prime is 1981447271. The next prime is 1981447331. The reversal of 1981447283 is 3827441891.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1981447283 is a prime.

It is a super-3 number, since 3×1981447283³ (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (1981447483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990723641 + 990723642.

It is an arithmetic number, because the mean of its divisors is an integer number (990723642).

Almost surely, 2^1981447283 is an apocalyptic number.

1981447283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1981447283 is an equidigital number, since it uses as much as digits as its factorization.

1981447283 is an evil number, because the sum of its binary digits is even.

The product of its digits is 387072, while the sum is 47.

The square root of 1981447283 is about 44513.4505851883. The cubic root of 1981447283 is about 1256.0131146192.

The spelling of 1981447283 in words is "one billion, nine hundred eighty-one million, four hundred forty-seven thousand, two hundred eighty-three".