Base | Representation |
---|---|
bin | 11100110101011010100… |
… | …110101000110010101101 |
3 | 21000102121010211112212201 |
4 | 130311122212220302231 |
5 | 224431103000021303 |
6 | 4114142153501501 |
7 | 263105263053160 |
oct | 34653246506255 |
9 | 7012533745781 |
10 | 1981500001453 |
11 | 6a4393103095 |
12 | 280040411891 |
13 | 114b1587c57b |
14 | 6bc958abad7 |
15 | 36823cab81d |
hex | 1cd5a9a8cad |
1981500001453 has 32 divisors (see below), whose sum is σ = 2392983797760. Its totient is φ = 1604649493440.
The previous prime is 1981500001447. The next prime is 1981500001483. The reversal of 1981500001453 is 3541000051891.
It is a de Polignac number, because none of the positive numbers 2k-1981500001453 is a prime.
It is a super-2 number, since 2×19815000014532 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1981500001483) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 55234000 + ... + 55269862.
It is an arithmetic number, because the mean of its divisors is an integer number (74780743680).
Almost surely, 21981500001453 is an apocalyptic number.
It is an amenable number.
1981500001453 is a deficient number, since it is larger than the sum of its proper divisors (411483796307).
1981500001453 is a wasteful number, since it uses less digits than its factorization.
1981500001453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41737.
The product of its (nonzero) digits is 21600, while the sum is 37.
The spelling of 1981500001453 in words is "one trillion, nine hundred eighty-one billion, five hundred million, one thousand, four hundred fifty-three".
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