Base | Representation |
---|---|
bin | 10010011101001001… |
… | …101001001101000011 |
3 | 1220011001002110001112 |
4 | 102131021221031003 |
5 | 311041000421123 |
6 | 13034210353535 |
7 | 1301032535501 |
oct | 223511511503 |
9 | 56131073045 |
10 | 19816420163 |
11 | 8449941851 |
12 | 3a1058b8ab |
13 | 1b3a64c507 |
14 | d5db79671 |
15 | 7aeaa6d78 |
hex | 49d269343 |
19816420163 has 8 divisors (see below), whose sum is σ = 19904071680. Its totient is φ = 19728962440.
The previous prime is 19816420123. The next prime is 19816420189. The reversal of 19816420163 is 36102461891.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 19816420163 - 222 = 19812225859 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 19816420163.
It is not an unprimeable number, because it can be changed into a prime (19816420123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 158456 + ... + 254442.
It is an arithmetic number, because the mean of its divisors is an integer number (2488008960).
Almost surely, 219816420163 is an apocalyptic number.
19816420163 is a deficient number, since it is larger than the sum of its proper divisors (87651517).
19816420163 is an equidigital number, since it uses as much as digits as its factorization.
19816420163 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96897.
The product of its (nonzero) digits is 62208, while the sum is 41.
The spelling of 19816420163 in words is "nineteen billion, eight hundred sixteen million, four hundred twenty thousand, one hundred sixty-three".
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