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1983016548451 is a prime number
BaseRepresentation
bin11100110110110100111…
…111110011100001100011
321000120111211111010021001
4130312310333303201203
5224442204214022301
64114552450412431
7263160666356041
oct34666477634143
97016454433231
101983016548451
116a4aa1165314
122803a4291117
13114cc7b16363
146bd9b07b391
15368b1ec3c01
hex1cdb4ff3863

1983016548451 has 2 divisors, whose sum is σ = 1983016548452. Its totient is φ = 1983016548450.

The previous prime is 1983016548419. The next prime is 1983016548511. The reversal of 1983016548451 is 1548456103891.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1983016548451 - 25 = 1983016548419 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1983016548392 and 1983016548401.

It is not a weakly prime, because it can be changed into another prime (1983016545451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991508274225 + 991508274226.

It is an arithmetic number, because the mean of its divisors is an integer number (991508274226).

Almost surely, 21983016548451 is an apocalyptic number.

1983016548451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1983016548451 is an equidigital number, since it uses as much as digits as its factorization.

1983016548451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4147200, while the sum is 55.

The spelling of 1983016548451 in words is "one trillion, nine hundred eighty-three billion, sixteen million, five hundred forty-eight thousand, four hundred fifty-one".