Base | Representation |
---|---|
bin | 11100110110110100111… |
… | …111110011100001100011 |
3 | 21000120111211111010021001 |
4 | 130312310333303201203 |
5 | 224442204214022301 |
6 | 4114552450412431 |
7 | 263160666356041 |
oct | 34666477634143 |
9 | 7016454433231 |
10 | 1983016548451 |
11 | 6a4aa1165314 |
12 | 2803a4291117 |
13 | 114cc7b16363 |
14 | 6bd9b07b391 |
15 | 368b1ec3c01 |
hex | 1cdb4ff3863 |
1983016548451 has 2 divisors, whose sum is σ = 1983016548452. Its totient is φ = 1983016548450.
The previous prime is 1983016548419. The next prime is 1983016548511. The reversal of 1983016548451 is 1548456103891.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1983016548451 - 25 = 1983016548419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1983016548392 and 1983016548401.
It is not a weakly prime, because it can be changed into another prime (1983016545451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991508274225 + 991508274226.
It is an arithmetic number, because the mean of its divisors is an integer number (991508274226).
Almost surely, 21983016548451 is an apocalyptic number.
1983016548451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1983016548451 is an equidigital number, since it uses as much as digits as its factorization.
1983016548451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4147200, while the sum is 55.
The spelling of 1983016548451 in words is "one trillion, nine hundred eighty-three billion, sixteen million, five hundred forty-eight thousand, four hundred fifty-one".
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