1985033 has 4 divisors (see below), whose sum is σ = 2010240. Its totient is φ = 1959828.

The previous prime is 1985017. The next prime is 1985041. The reversal of 1985033 is 3305891.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1985033 - 2⁴ = 1985017 is a prime.

It is a super-2 number, since 2×1985033² = 7880712022178, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1984987 and 1985005.

It is not an unprimeable number, because it can be changed into a prime (1985003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12485 + ... + 12642.

It is an arithmetic number, because the mean of its divisors is an integer number (502560).

2^1985033 is an apocalyptic number.

It is an amenable number.

1985033 is a deficient number, since it is larger than the sum of its proper divisors (25207).

1985033 is an equidigital number, since it uses as much as digits as its factorization.

1985033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25206.

The product of its (nonzero) digits is 3240, while the sum is 29.

The square root of 1985033 is about 1408.9119915736. The cubic root of 1985033 is about 125.6770304181.

The spelling of 1985033 in words is "one million, nine hundred eighty-five thousand, thirty-three".