Base | Representation |
---|---|
bin | 101101011101101100011100… |
… | …001110110010011101010001 |
3 | 222012222021210210101001112011 |
4 | 231131230130032302131101 |
5 | 202202011040040312032 |
6 | 1545132554042102521 |
7 | 60055050466661344 |
oct | 5535543416623521 |
9 | 865867723331464 |
10 | 199952676104017 |
11 | 587904a99a5911 |
12 | 1a5142027aaa41 |
13 | 87755c1a8a075 |
14 | 3753a928a645b |
15 | 181b36460e247 |
hex | b5db1c3b2751 |
199952676104017 has 2 divisors, whose sum is σ = 199952676104018. Its totient is φ = 199952676104016.
The previous prime is 199952676103987. The next prime is 199952676104023. The reversal of 199952676104017 is 710401676259991.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 193632123110976 + 6320552993041 = 13915176^2 + 2514071^2 .
It is a cyclic number.
It is not a de Polignac number, because 199952676104017 - 227 = 199952541886289 is a prime.
It is not a weakly prime, because it can be changed into another prime (199952676104057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99976338052008 + 99976338052009.
It is an arithmetic number, because the mean of its divisors is an integer number (99976338052009).
Almost surely, 2199952676104017 is an apocalyptic number.
It is an amenable number.
199952676104017 is a deficient number, since it is larger than the sum of its proper divisors (1).
199952676104017 is an equidigital number, since it uses as much as digits as its factorization.
199952676104017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51438240, while the sum is 67.
The spelling of 199952676104017 in words is "one hundred ninety-nine trillion, nine hundred fifty-two billion, six hundred seventy-six million, one hundred four thousand, seventeen".
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