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2000010112113 = 313127403797721
BaseRepresentation
bin11101000110101001111…
…001000110110001110001
321002012101010212121011210
4131012221321012301301
5230232010042041423
64130443021430333
7264332054312316
oct35065171066161
97065333777153
102000010112113
11701221628202
1228374740b3a9
131167a5694c80
146cb2dd62d0d
1537058d28b93
hex1d1a9e46c71

2000010112113 has 16 divisors (see below), whose sum is σ = 2894422071296. Its totient is φ = 1221084305280.

The previous prime is 2000010112097. The next prime is 2000010112117. The reversal of 2000010112113 is 3112110100002.

It is not a de Polignac number, because 2000010112113 - 24 = 2000010112097 is a prime.

It is a super-3 number, since 3×20000101121133 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2000010112117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 201893908 + ... + 201903813.

It is an arithmetic number, because the mean of its divisors is an integer number (180901379456).

Almost surely, 22000010112113 is an apocalyptic number.

It is an amenable number.

2000010112113 is a deficient number, since it is larger than the sum of its proper divisors (894411959183).

2000010112113 is a wasteful number, since it uses less digits than its factorization.

2000010112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 403797864.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 2000010112113 its reverse (3112110100002), we get a palindrome (5112120212115).

The spelling of 2000010112113 in words is "two trillion, ten million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 13 39 127 381 1651 4953 403797721 1211393163 5249370373 15748111119 51282310567 153846931701 666670037371 2000010112113