Base | Representation |
---|---|
bin | 111011100110101… |
… | …1011111110001011 |
3 | 12011101101002111221 |
4 | 1313031123332023 |
5 | 13044000324042 |
6 | 530243102511 |
7 | 100363546201 |
oct | 16715337613 |
9 | 5141332457 |
10 | 2000011147 |
11 | 936a54a82 |
12 | 479971a37 |
13 | 25b47c464 |
14 | 14d89d071 |
15 | ba8b5d67 |
hex | 7735bf8b |
2000011147 has 2 divisors, whose sum is σ = 2000011148. Its totient is φ = 2000011146.
The previous prime is 2000011109. The next prime is 2000011199. The reversal of 2000011147 is 7411100002.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2000011147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2000011147.
It is not a weakly prime, because it can be changed into another prime (2000051147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000005573 + 1000005574.
It is an arithmetic number, because the mean of its divisors is an integer number (1000005574).
Almost surely, 22000011147 is an apocalyptic number.
2000011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000011147 is an equidigital number, since it uses as much as digits as its factorization.
2000011147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 16.
The square root of 2000011147 is about 44721.4841770709. The cubic root of 2000011147 is about 1259.9233906138.
Adding to 2000011147 its reverse (7411100002), we get a palindrome (9411111149).
The spelling of 2000011147 in words is "two billion, eleven thousand, one hundred forty-seven".
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