Base | Representation |
---|---|
bin | 1011101001000110010… |
… | …1011010100011000011 |
3 | 201010021002222112122221 |
4 | 2322101211122203003 |
5 | 11234110304000003 |
6 | 231514521511511 |
7 | 20310313306663 |
oct | 2722145324303 |
9 | 633232875587 |
10 | 200011000003 |
11 | 77907aa4711 |
12 | 3291b342597 |
13 | 15b266a0c59 |
14 | 99757461a3 |
15 | 53093e87bd |
hex | 2e9195a8c3 |
200011000003 has 4 divisors (see below), whose sum is σ = 210537894760. Its totient is φ = 189484105248.
The previous prime is 200010999983. The next prime is 200011000039. The reversal of 200011000003 is 300000110002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200011000003 - 213 = 200010991811 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 200011000003.
It is not an unprimeable number, because it can be changed into a prime (200011000093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5263447350 + ... + 5263447387.
It is an arithmetic number, because the mean of its divisors is an integer number (52634473690).
Almost surely, 2200011000003 is an apocalyptic number.
200011000003 is a deficient number, since it is larger than the sum of its proper divisors (10526894757).
200011000003 is a wasteful number, since it uses less digits than its factorization.
200011000003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10526894756.
The product of its (nonzero) digits is 6, while the sum is 7.
Adding to 200011000003 its reverse (300000110002), we get a palindrome (500011110005).
The spelling of 200011000003 in words is "two hundred billion, eleven million, three", and thus it is an aban number.
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