Base | Representation |
---|---|
bin | 1001000110000110111100… |
… | …11110000011010010100011 |
3 | 2121211002100001120220122012 |
4 | 10203003132132003102203 |
5 | 10110144223114244143 |
6 | 110312213434103135 |
7 | 4133013623111024 |
oct | 443033636032243 |
9 | 77732301526565 |
10 | 20001100149923 |
11 | 6411467674a52 |
12 | 22b041bb7aaab |
13 | b211321b7a19 |
14 | 4d20b63d8c4b |
15 | 24a41b74b418 |
hex | 1230de7834a3 |
20001100149923 has 2 divisors, whose sum is σ = 20001100149924. Its totient is φ = 20001100149922.
The previous prime is 20001100149913. The next prime is 20001100149967. The reversal of 20001100149923 is 32994100110002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20001100149923 - 218 = 20001099887779 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20001100149923.
It is not a weakly prime, because it can be changed into another prime (20001100149913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000550074961 + 10000550074962.
It is an arithmetic number, because the mean of its divisors is an integer number (10000550074962).
Almost surely, 220001100149923 is an apocalyptic number.
20001100149923 is a deficient number, since it is larger than the sum of its proper divisors (1).
20001100149923 is an equidigital number, since it uses as much as digits as its factorization.
20001100149923 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 32.
Adding to 20001100149923 its reverse (32994100110002), we get a palindrome (52995200259925).
The spelling of 20001100149923 in words is "twenty trillion, one billion, one hundred million, one hundred forty-nine thousand, nine hundred twenty-three".
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