Base | Representation |
---|---|
bin | 11101000110101111111… |
… | …011000110111011100011 |
3 | 21002012122012021111022021 |
4 | 131012233323012323203 |
5 | 230232211443102243 |
6 | 4130501034322311 |
7 | 264334423353553 |
oct | 35065773067343 |
9 | 7065565244267 |
10 | 2000111300323 |
11 | 701273760424 |
12 | 283775289397 |
13 | 1167c0633556 |
14 | 6cb3d583163 |
15 | 37062b656ed |
hex | 1d1afec6ee3 |
2000111300323 has 4 divisors (see below), whose sum is σ = 2000114459728. Its totient is φ = 2000108140920.
The previous prime is 2000111300303. The next prime is 2000111300347. The reversal of 2000111300323 is 3230031110002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2000111300323 - 237 = 1862672346851 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2000111300297 and 2000111300306.
It is not an unprimeable number, because it can be changed into a prime (2000111300303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265863 + ... + 2017648.
It is an arithmetic number, because the mean of its divisors is an integer number (500028614932).
Almost surely, 22000111300323 is an apocalyptic number.
2000111300323 is a deficient number, since it is larger than the sum of its proper divisors (3159405).
2000111300323 is an equidigital number, since it uses as much as digits as its factorization.
2000111300323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3159404.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 2000111300323 its reverse (3230031110002), we get a palindrome (5230142410325).
The spelling of 2000111300323 in words is "two trillion, one hundred eleven million, three hundred thousand, three hundred twenty-three".
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