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2000112000001 = 5473656511883
BaseRepresentation
bin11101000110101111111…
…101110001110000000001
321002012122020121001002021
4131012233331301300001
5230232212133000001
64130501101321441
7264334432326463
oct35065775616001
97065566531067
102000112000001
11701274099075
12283775566281
131167c0819b6b
146cb3d6c6133
1537062c52ba1
hex1d1aff71c01

2000112000001 has 4 divisors (see below), whose sum is σ = 2003768512432. Its totient is φ = 1996455487572.

The previous prime is 2000111999981. The next prime is 2000112000017. The reversal of 2000112000001 is 1000002110002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2000112000001 - 211 = 2000111997953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2000112000041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1828255395 + ... + 1828256488.

It is an arithmetic number, because the mean of its divisors is an integer number (500942128108).

Almost surely, 22000112000001 is an apocalyptic number.

It is an amenable number.

2000112000001 is a deficient number, since it is larger than the sum of its proper divisors (3656512431).

2000112000001 is an equidigital number, since it uses as much as digits as its factorization.

2000112000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3656512430.

The product of its (nonzero) digits is 4, while the sum is 7.

Adding to 2000112000001 its reverse (1000002110002), we get a palindrome (3000114110003).

The spelling of 2000112000001 in words is "two trillion, one hundred twelve million, one", and thus it is an aban number.

Divisors: 1 547 3656511883 2000112000001