Base | Representation |
---|---|
bin | 11101000110110000100… |
… | …000001101000101001001 |
3 | 21002012122212120112211121 |
4 | 131012300200031011021 |
5 | 230232221440243331 |
6 | 4130502022555241 |
7 | 264334602125122 |
oct | 35066040150511 |
9 | 7065585515747 |
10 | 2000121024841 |
11 | 7012791a2615 |
12 | 283778598b21 |
13 | 1167c26598c4 |
14 | 6cb40995049 |
15 | 37063936c11 |
hex | 1d1b080d149 |
2000121024841 has 2 divisors, whose sum is σ = 2000121024842. Its totient is φ = 2000121024840.
The previous prime is 2000121024809. The next prime is 2000121024851. The reversal of 2000121024841 is 1484201210002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1167274964025 + 832846060816 = 1080405^2 + 912604^2 .
It is a cyclic number.
It is not a de Polignac number, because 2000121024841 - 25 = 2000121024809 is a prime.
It is a super-2 number, since 2×20001210248412 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2000121024851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000060512420 + 1000060512421.
It is an arithmetic number, because the mean of its divisors is an integer number (1000060512421).
Almost surely, 22000121024841 is an apocalyptic number.
It is an amenable number.
2000121024841 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000121024841 is an equidigital number, since it uses as much as digits as its factorization.
2000121024841 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 2000121024841 its reverse (1484201210002), we get a palindrome (3484322234843).
The spelling of 2000121024841 in words is "two trillion, one hundred twenty-one million, twenty-four thousand, eight hundred forty-one".
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