200013103244041 has 8 divisors (see below), whose sum is σ = 202684766356800. Its totient is φ = 197347675052592.

The previous prime is 200013103244039. The next prime is 200013103244099. The reversal of 200013103244041 is 140442301310002.

200013103244041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 200013103244041 - 2¹ = 200013103244039 is a prime.

It is a super-3 number, since 3×200013103244041³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200013103243997 and 200013103244015.

It is not an unprimeable number, because it can be changed into a prime (200013103244441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1558665741 + ... + 1558794058.

It is an arithmetic number, because the mean of its divisors is an integer number (25335595794600).

Almost surely, 2^{200013103244041} is an apocalyptic number.

It is an amenable number.

200013103244041 is a deficient number, since it is larger than the sum of its proper divisors (2671663112759).

200013103244041 is an equidigital number, since it uses as much as digits as its factorization.

200013103244041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3117460655.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 200013103244041 its reverse (140442301310002), we get a palindrome (340455404554043).

The spelling of 200013103244041 in words is "two hundred trillion, thirteen billion, one hundred three million, two hundred forty-four thousand, forty-one".