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20001424434011 = 37353623121807
BaseRepresentation
bin1001000110000111100011…
…10011000110001101011011
32121211010011122210020202222
410203003301303012031123
510110200404123342021
6110312305540414255
74133024641351466
oct443036163061533
977733148706688
1020001424434011
116411613725429
1222b04b06a738b
13b21184438bb7
144d21074d02dd
1524a439e556ab
hex1230f1cc635b

20001424434011 has 4 divisors (see below), whose sum is σ = 20055047556192. Its totient is φ = 19947801311832.

The previous prime is 20001424434001. The next prime is 20001424434031. The reversal of 20001424434011 is 11043442410002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20001424434011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20001424434001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26811560531 + ... + 26811561276.

It is an arithmetic number, because the mean of its divisors is an integer number (5013761889048).

Almost surely, 220001424434011 is an apocalyptic number.

20001424434011 is a deficient number, since it is larger than the sum of its proper divisors (53623122181).

20001424434011 is an equidigital number, since it uses as much as digits as its factorization.

20001424434011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53623122180.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 20001424434011 its reverse (11043442410002), we get a palindrome (31044866844013).

The spelling of 20001424434011 in words is "twenty trillion, one billion, four hundred twenty-four million, four hundred thirty-four thousand, eleven".

Divisors: 1 373 53623121807 20001424434011